JEE Advanced · Chemistry · 7. Chemical Equilibrium
Paragraph:
Thermal decomposition of gaseous \(\mathrm{X}_{2}\) to gaseous \(\mathrm{X}\) at \(298 \mathrm{~K}\) takes place according to the following equation:
\(\mathrm{X}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{X}(\mathrm{g})\)
The standard reaction Gibbs energy, \(\Delta_{r} G^{\circ}\), of this reaction is positive. At the start of the reaction, there is one mole of \(\mathrm{X}_{2}\) and no \(\mathrm{X}\). As the reaction proceeds, the number of moles of \(\mathrm{X}\) formed is given by \(\beta\). Thus, \(\beta_{\text {equilibrium }}\) is the number of moles of \(\mathrm{X}\) formed at equilibrium. The reaction is carried out at a constant total pressure of \(2\) bar. Consider the gases to behave ideally. (Given : \(R=0.083 \mathrm{~L}\) bar \(\mathrm{K}^{-1} \mathrm{~mol}^{-1}\) )
Question:
The INCORRECT statement among the following, for this reaction, is
- A Decrease in the total pressure will result in formation of more moles of gaseous X
- B At the start of the reaction, dissociation of gaseous takes place spontaneously
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
A] On decreasing Q will be less than reaction will move in forward direction
B] At the start of the reaction ln Q
C] If
Since it is given that
This is incorrect
D]
B] At the start of the reaction ln Q
C] If
Since it is given that
This is incorrect
D]
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