JEE Advanced · Chemistry · 23. Coordination Compounds
Statement \(\mathbf{1}\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4\) is paramagnetic.
Statement 2 The \(\mathrm{Fe}\) in \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4\) has three unpaired electrons.
- A Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
- B Statement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
- C Statement 1 is true, Statement 2 is false.
- D Statement 1 is false, Statement 2 is true
Answer & Solution
Correct Answer
(A) Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
Step-by-step Solution
Detailed explanation
The oxidation number of \(\mathrm{Fe}\) in the complex, \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4\) is \(+1\) [ \(\mathrm{NO}\) has \(+1\) charge ]
\(
\mathrm{Fe}^{+}=[\mathrm{Ar}] 3 d^6 4 s^1
\)
\(\mathrm{NO}^{+}\)causes pairing of 4 s electron inside .
Thus, the configuration is \(3 d^7\) and number of unpaired electrons \(=3\)
\(
\mathrm{Fe}^{+}=[\mathrm{Ar}] 3 d^6 4 s^1
\)
\(\mathrm{NO}^{+}\)causes pairing of 4 s electron inside .
Thus, the configuration is \(3 d^7\) and number of unpaired electrons \(=3\)
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