JEE Advanced · Chemistry · 21. p Block (G15-18)

Paragraph:
The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other interatomic interactions.
The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers $+2,+4$ and $+6 . \mathrm{XeF}_4$ reacts violently with water to give $\mathrm{XeO}_3$. The compounds of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell.
Question:
$\mathrm{XeF}_4$ and $\mathrm{XeF}_6$ are expected to be

A oxidising
B reducing
C unreactive
D strongly basic

Verified Solution

Answer & Solution

Correct Answer

(A) oxidising

Step-by-step Solution

Detailed explanation

$\mathrm{XeF}_4$ oxidises potassium iodide
$
\mathrm{XeF}_4+4 \mathrm{I}^{-} \longrightarrow 2 \mathrm{I}_2+4 \mathrm{~F}^{-1}+\mathrm{Xe}
$
$\mathrm{XeF}_6$ oxidises hydrogen like other xenon fluorides.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Among the complex ions,
$\left[\mathrm{Co}\left(\mathrm{NH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{NH}_{2}\right)_{2} \mathrm{Cl}_{2}\right]^{+},$$\left[\mathrm{CrCl}_{2}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\right]^{3-},\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}(\mathrm{OH})_{2}\right]^{+}$, $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{CN})_{4}\right]^{-},$$\left[\mathrm{Co}(\mathrm{NH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{NH}_{2})_{2}\left(\mathrm{NH}_{3}\right) \mathrm{Cl}\right]^{2+}$ and $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}\right]^{2+}$, the number of complex ion(s) that show(s) cis-trans isomerism is

JEE Advanced 2015 Medium

Match the compounds in LIST-

I

with the observations in LIST-

II

, and choose the correct option.

	LIST- $I$		LIST- $II$
$(I)$	Aniline	$(P)$	Sodium fusion extract of the compound on boiling with ${FeSO}_{4}$ , followed by acidification with conc. $H_{2} {SO}_{4}$ , gives Prussian blue color.
$(II)$	$o -$ Cresol	$(Q)$	Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
$(III)$	Cysteine	$(R)$	Addition of the compound to a saturated solution of ${NaHCO}_{3}$ results in effervescence.
$(IV)$	Caprolactam	$(S)$	The compound reacts with bromine water to give a white precipitate.
		$(T)$	Treating the compound with neutral ${FeCl}_{3}$ solution produces violet color.

JEE Advanced 2022 Hard

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From JEE Advanced

Match List I with List II and select the correct answer using the codes given below the lists:

	$\text{List I}$		$\text{List II}$
a.	Boltzmann constant	p.	$\left[M L^2 T^{-1}\right]$
b.	Coefficient of viscosity	q.	$\left[M L^{-1} T^{-1}\right]$
c.	Planck constant	r.	$\left[M L T^{-3} K^{-1}\right]$
d.	Thermal conductivity	s.	$\left[M L^2 T^{-2} K^{-1}\right]$

JEE Advanced 2013 Easy

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	\(\text{List I}\)		\(\text{List II}\)
a.	Boltzmann constant	p.	\(\left[M L^2 T^{-1}\right]\)
b.	Coefficient of viscosity	q.	\(\left[M L^{-1} T^{-1}\right]\)
c.	Planck constant	r.	\(\left[M L T^{-3} K^{-1}\right]\)
d.	Thermal conductivity	s.	\(\left[M L^2 T^{-2} K^{-1}\right]\)