JEE Advanced · Mathematics · 25. AOD
Let \(f(x)=2+\cos x\) for all real \(x\).
Statement I For each real \(t\), there exists a point \(c\) in \([t, t+\pi]\) such that \(f^{\prime}(c)=0\).
Statement II \(f(t)=f(t+2 \pi)\) for each real \(t\).
- A Statement I is true, Statement II is true; Statement II is a correct explanation for Statement I
- B Statement I is True, Statement II is true; Statement II is not a correct explanation for Statement I
- C Statement I is true, Statement II is false
- D Statement I is false, Statement II is true
Answer & Solution
Correct Answer
(B) Statement I is True, Statement II is true; Statement II is not a correct explanation for Statement I
Step-by-step Solution
Detailed explanation
\(f(x)=2+\cos x \forall x \in R\)
Statement I There exists a point \(c \in[t, t+\pi]\), where \(f^{\prime}(c)=0\) Hence, Statement 1 is true.
Statement II \(f(t)=f(t+2 \pi)\) is true.
But Statement II is not a correct explanation for Statement I.
Statement I There exists a point \(c \in[t, t+\pi]\), where \(f^{\prime}(c)=0\) Hence, Statement 1 is true.
Statement II \(f(t)=f(t+2 \pi)\) is true.
But Statement II is not a correct explanation for Statement I.
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