JEE Advanced · Chemistry · 23. Coordination Compounds
Total number of geometrical isomers for the complex \(\left[\mathrm{RhCl}(\mathrm{CO})\left(\mathrm{PPh}_3\right)\left(\mathrm{NH}_3\right)\right]\) is
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
\([M(a b c d)]\) complex is square planar so will have 3 geometrical isomers.


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