JEE Advanced · Chemistry · 6. Thermodynamics (C)
Considering ideal gas behavior, the expansion work done (in kJ) when 144 g of water is electrolyzed completely under constant pressure at 300 K is _____
Use: Universal gas constant \((\mathrm{R})=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\); Atomic mass (in amu): \(\mathrm{H}=1, \mathrm{O}=16\) (mark absolute value as answer)
- A 29.88
- B 32.55
- C 12.55
- D 1.348
Answer & Solution
Correct Answer
(A) 29.88
Step-by-step Solution
Detailed explanation
in official answer key answer was [-29.95 to -29.8] OR [29.8 to 29.95], we have updated the question to make it valid.
\(\begin{array}{lcc}
\mathrm{H}_2 \mathrm{O}(l) \rightarrow & \mathrm{H}_2(\mathrm{~g})+ & \frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \\
144 \mathrm{~g} & - & - \\
8 \mathrm{~mol} & 8 \mathrm{~mol} & 4 \mathrm{~mol} \\
\mathrm{~W}=-\mathrm{P} \Delta \mathrm{~V}= & -(\Delta \mathrm{n}) \mathrm{RT}
\end{array}\)
\(\begin{aligned}
&\text { Change in gaseous moles }=12\\
&\Rightarrow \mathrm{W}=-\frac{12 \times 8.3 \times 300}{1000} \mathrm{~kJ}=-29.88 \mathrm{~kJ} .
\end{aligned}\)
\(\begin{array}{lcc}
\mathrm{H}_2 \mathrm{O}(l) \rightarrow & \mathrm{H}_2(\mathrm{~g})+ & \frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \\
144 \mathrm{~g} & - & - \\
8 \mathrm{~mol} & 8 \mathrm{~mol} & 4 \mathrm{~mol} \\
\mathrm{~W}=-\mathrm{P} \Delta \mathrm{~V}= & -(\Delta \mathrm{n}) \mathrm{RT}
\end{array}\)
\(\begin{aligned}
&\text { Change in gaseous moles }=12\\
&\Rightarrow \mathrm{W}=-\frac{12 \times 8.3 \times 300}{1000} \mathrm{~kJ}=-29.88 \mathrm{~kJ} .
\end{aligned}\)
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