JEE Advanced · Chemistry · 31. Practical Chemistry
A solution of a metal ion when treated with \(\mathrm{KI}\) gives a red precipitate which dissolved in excess KI to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitqte. The metal ion is
- A \(\mathrm{Pb}^{2+}\)
- B \(\mathrm{Hg}^{2+}\)
- C \(\mathrm{Cu}^{2+}\)
- D \(\mathrm{Co}^2\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Hg}^{2+}\)
Step-by-step Solution
Detailed explanation
\(
\begin{aligned}
& \mathrm{Hg}^{2+}+2 \mathrm{I}^{-} \longrightarrow \mathrm{HgI}_2, \mathrm{HgI}_2+\mathrm{H}^{-} \\
& \text {(Excess) }\left.\longrightarrow \mathrm{HgI}_4\right]^{2-} \\
& \text { Soluble }^{2-} \\
& \mathrm{Hg}^{2+}+\mathrm{Co}(\mathrm{SCN})_2 \longrightarrow \mathrm{Hg}(\mathrm{SCN})_2
\end{aligned}
\)
Blue crystalline ppt.
\begin{aligned}
& \mathrm{Hg}^{2+}+2 \mathrm{I}^{-} \longrightarrow \mathrm{HgI}_2, \mathrm{HgI}_2+\mathrm{H}^{-} \\
& \text {(Excess) }\left.\longrightarrow \mathrm{HgI}_4\right]^{2-} \\
& \text { Soluble }^{2-} \\
& \mathrm{Hg}^{2+}+\mathrm{Co}(\mathrm{SCN})_2 \longrightarrow \mathrm{Hg}(\mathrm{SCN})_2
\end{aligned}
\)
Blue crystalline ppt.
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