JEE Advanced · Chemistry · 21. p Block (G15-18)

With respect to hypochlorite, chlorate and perchlorate ions, choose the correct statement(s).

A The hypochlorite ion is the strongest conjugate base.
B The molecular shape of only chlorate ion is influenced by the lone pair of electrons of $Cl$ .
C The hypochlorite and chlorate ions disproportionate to give rise to identical set of ions.
D The hypochlorite ion oxidizes the sulfite ion.

Verified Solution

Answer & Solution

Correct Answer

(A) The hypochlorite ion is the strongest conjugate base.

Step-by-step Solution

Detailed explanation

(A)

since

HOCl

is weakest oxyacid of chlorine. Therefore

ClO

- become strongest conjugate base.

(B)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Let $z_k=\cos \left(\frac{2 k \pi}{10}\right)+i \sin \left(\frac{2 k \pi}{10}\right) ; k=1,2, \ldots, 9$

List - I	List - II
(A) For each $z_k$ there exists a $z_j$ such $z_k \cdot z_j=1$	(P) True
(B) There exists a $k \in\{1,2, \ldots, 9\}$ such that $z_1 \cdot z=z_k$ has no solution z in the set of complex numbers	(Q) False
(C) $\frac{\left\|1-z_1\right\|\left\|1-z_2\right\|\ldots\left\|1-z_9\right\|}{10}$ equals	(R) 1
(D) $1-\sum_{k=1}^9 \cos \left(\frac{2 k \pi}{10}\right)$ equals	(S) 2

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Column I	Column II
A. Cellulose	p. Natural polymer
B. Nylon-6,6	q. Synthetic polymer
C. Protein	r. Amide linkage
D. Sucrose	s. Glycoside linkage

	LIST -I		LIST -II
A)	$d s p^{2}$	P)	${[F e F_{6}]}^{4 -}$
B)	$s p^{3}$	Q)	$[T i {(H_{2} O)}_{3} C l_{3}]$
C)	$s p^{3} d^{2}$	R)	${[C r {(N H_{3})}_{6}]}^{3 +}$
D)	$d^{2} s p^{3}$	S)	${[F e C l_{4}]}^{2 -}$
		T)	$N i {(C O)}_{4}$
		U)	${[N i {(C N)}_{4}]}^{2 -}$

List - I	List - II
(A) For each \(z_k\) there exists a \(z_j\) such \(z_k \cdot z_j=1\)	(P) True
(B) There exists a \(k \in\{1,2, \ldots, 9\}\) such that \(z_1 \cdot z=z_k\) has no solution z in the set of complex numbers	(Q) False
(C) \(\frac{\left\|1-z_1\right\|\left\|1-z_2\right\|\ldots\left\|1-z_9\right\|}{10}\) equals	(R) 1
(D) \(1-\sum_{k=1}^9 \cos \left(\frac{2 k \pi}{10}\right)\) equals	(S) 2