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JEE Advanced · Chemistry · 17. Electrochemistry

Some standard electrode potentials at 298 K are given below: Pb2+/Pb-0.13 V Ni2+/Ni-0.24 V Cd2+/Cd-0.40 V Fe2+/Fe-0.44 V To a solution containing 0.001 M of X2+ and 0.1 M of Y2+, the metal rods X and Y are inserted (at 298 K) and connected by a conducting wire. This resulted in dissolution of X. The correct combination(s) of X and Y, respectively, is(are) (Given: Gas constant, R=8.314 J K-1 mol-1, Faraday constant, F=96500 C mol-1)

  1. A Cd and Ni
  2. B Cd and Fe
  3. C Ni and Pb
  4. D Ni and Fe
Verified Solution

Answer & Solution

Correct Answer

(A) Cd and Ni

Step-by-step Solution

Detailed explanation

Since X is getting dissolved, so reaction is XX2++2e-  AnodeY2++2e-Y  cathodeY2++XX2++Y
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