JEE Advanced · Chemistry · 12. p Block (G13-14)
\(\mathrm{B}(\mathrm{OH})_3+\mathrm{NaOH} \rightleftharpoons \mathrm{NaBO}_2+\mathrm{Na}[\mathrm{B}\)\((\mathrm{OH})_4]+\mathrm{H}_2 \mathrm{O}\).
How can this reaction is made to proceed in forward direction?
- A Addition of cis 1, 2 diol
- B Addition of borax
- C Addition of trans 1, 2 diol
- D Addition of \(\mathrm{Na}_2 \mathrm{HPO}_4\)
Answer & Solution
Correct Answer
(A) Addition of cis 1, 2 diol
Step-by-step Solution
Detailed explanation
\(\text B (\text{OH})_3+ \text{NaOH} \rightleftharpoons \text{NaBO} _2+ \text{Na} ^{+}\)\(\left[\text B (\text{OH})_4\right]^{-}+\text H _2\text O\)
This reaction is reversible reaction because sodium metaborate, \(\mathrm{Na}^{+}\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}\)formed by the reaction between \(\mathrm{B}(\mathrm{OH})_3\) and \(\mathrm{NaOH}\) gets hydrolysed to regenerate \(\mathrm{B}(\mathrm{OH})_3\) and \(\mathrm{NaOH}\)
\(\text{Na} ^{+}\left[\text B (\text{OH})_4\right]^{-} \xrightarrow[\text {Hydrolysis}]{ } \text{NaOH}\) \(+\text{ B} (\text{OH} )_3\)
If, some quantity of polyhydroxy compound like cis-1, 3-diol, catechol, glycerol etc. is added to the reaction mixture. The \(\mathrm{B}(\mathrm{OH})_3\) combines with such polyhydroxy compound to give chelated complex compound. Due to complex compound formation, stability increases and due to higher stability of complex, reaction moves in forward direction.
This reaction is reversible reaction because sodium metaborate, \(\mathrm{Na}^{+}\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}\)formed by the reaction between \(\mathrm{B}(\mathrm{OH})_3\) and \(\mathrm{NaOH}\) gets hydrolysed to regenerate \(\mathrm{B}(\mathrm{OH})_3\) and \(\mathrm{NaOH}\)
\(\text{Na} ^{+}\left[\text B (\text{OH})_4\right]^{-} \xrightarrow[\text {Hydrolysis}]{ } \text{NaOH}\) \(+\text{ B} (\text{OH} )_3\)
If, some quantity of polyhydroxy compound like cis-1, 3-diol, catechol, glycerol etc. is added to the reaction mixture. The \(\mathrm{B}(\mathrm{OH})_3\) combines with such polyhydroxy compound to give chelated complex compound. Due to complex compound formation, stability increases and due to higher stability of complex, reaction moves in forward direction.
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