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JEE Advanced · Chemistry · 1. Mole Concept

A student performs a titration with different burettes and finds titre values of \(25.2 \mathrm{~mL}, 25.25 \mathrm{~mL}\), and \(25.0 \mathrm{~mL}\).
The number of significant figures in the average titre value is

  1. A 1
  2. B 2
  3. C 3
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(C) 3

Step-by-step Solution

Detailed explanation

Average
\(
\begin{aligned}
& =\frac{25.2+25.25+25.0}{3}=\frac{75.45}{3} \\
& =25.15=25.2 \mathrm{~mL}
\end{aligned}
\)
Number of significant figure is 3 .
Basics in chemistry
Rule application
III (Difficulty level is high because of shear ignorance of such topics)
From JEE Advanced
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