JEE Advanced · Chemistry · 18. Chemical Kinetics
A positron is emitted from \({ }_{11}^{23} \mathrm{Na}\). The ratio of the atomic mass and atomic number of the resulting nuclide is
- A 22/10
- B 22/11
- C 23/10
- D \(23 / 12\)
Answer & Solution
Correct Answer
(C) 23/10
Step-by-step Solution
Detailed explanation
\({ }_{11}^{23} \mathrm{Na} \longrightarrow{ }_{10}^{23} \mathrm{Na}+{ }_{-1}^0 e\)
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