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JEE Advanced · Chemistry · 18. Chemical Kinetics

A positron is emitted from \({ }_{11}^{23} \mathrm{Na}\). The ratio of the atomic mass and atomic number of the resulting nuclide is

  1. A 22/10
  2. B 22/11
  3. C 23/10
  4. D \(23 / 12\)
Verified Solution

Answer & Solution

Correct Answer

(C) 23/10

Step-by-step Solution

Detailed explanation

\({ }_{11}^{23} \mathrm{Na} \longrightarrow{ }_{10}^{23} \mathrm{Na}+{ }_{-1}^0 e\)
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