JEE Advanced · Chemistry · 2. Atomic Structure
Given, that the abundances of isotopes, \({ }_{54} \mathrm{Fe},{ }_{56} \mathrm{~F}\) and \({ }_{57} \mathrm{Fe}\) are \(5 \%\), \(90 \%\) and \(5 \%\), respectively, the atomic mass of \(\mathrm{Fe}\) is
- A \(55.85\)
- B \(55.95\)
- C \(55.75\)
- D \(56.05\)
Answer & Solution
Correct Answer
(B) \(55.95\)
Step-by-step Solution
Detailed explanation
Average atomic weight
\(\frac{54 \times 5+56 \times 90+57 \times 5}{100}=55.95\)
\(\frac{54 \times 5+56 \times 90+57 \times 5}{100}=55.95\)
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