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GUJCET · Maths · Three Dimensional Geometry
The Cartesian equation of line which passes through point \((5,-2,4)\) and parellel to the vector \(3 \hat{i}+2 \hat{j}-8 \hat{k}\) is _________ .
- A \(\frac{x-3}{5}=\frac{y+2}{-2}=\frac{z+8}{4}\)
- B \(\frac{x-5}{3}=\frac{y+2}{2}=\frac{z-4}{-8}\)
- C \(\frac{x-3}{5}=\frac{y-2}{2}=\frac{z+8}{-4}\)
- D \(\frac{x-5}{3}=\frac{y-2}{2}=\frac{z+4}{-8}\)
Answer & Solution
Correct Answer
(B) \(\frac{x-5}{3}=\frac{y+2}{2}=\frac{z-4}{-8}\)
Step-by-step Solution
Detailed explanation
Equation of a line: \( \frac{x - x_1}{a} = \frac{y - y_1}{b} = \frac{z - z_1}{c} \) Substitute \( (x_1, y_1, z_1) = (5, -2, 4) \) and \( (a, b, c) = (3, 2, -8) \):
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