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GUJCET · Maths · Continuity and Differentiability

If \(x=\sqrt{10^{\sin ^{-1} t}}, y=\sqrt{10^{\cos ^{-1} t}}\) then, \(\frac{d y}{d x}=\) _________

  1. A \(0\)
  2. B \(\frac{y}{x}\)
  3. C \(-\frac{y}{x}\)
  4. D \(-\frac{x}{y}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-\frac{y}{x}\)

Step-by-step Solution

Detailed explanation

\(x^2 = 10^{\sin^{-1} t}, y^2 = 10^{\cos^{-1} t}\) \(x^2 y^2 = 10^{\sin^{-1} t} \cdot 10^{\cos^{-1} t} = 10^{\sin^{-1} t + \cos^{-1} t}\)