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GUJCET · Physics · Magnetism And Matter
The magnetic susceptibility of a paramagnetic material is \(1.0 \times 10^{-5}\) at \(27^{\circ} C\) temperature. Then at what temperature its magnetic susceptibility would be \(1.5 \times 10^{-5}\) ?
- A \(18{ }^{\circ} C\)
- B \(200^{\circ} C\)
- C \(-73^{\circ} C\)
- D \(-18^{\circ} C\)
Answer & Solution
Correct Answer
(C) \(-73^{\circ} C\)
Step-by-step Solution
Detailed explanation
C
According to Curie law for paramagnetic substance
\(\chi_m \propto \frac{1}{T}\)
\(\frac{\chi_{m_1}}{\chi_{m_2}}=\frac{ T _2}{T_1}\)
\(\therefore \quad \frac{1.0 \times 10^{-5}}{1.5 \times 10^{-5}}=\frac{ T _2}{300}\)
\(\begin{aligned} T _2 =\frac{300}{1.5} \\ =200 K \\ =-73{ }^{\circ} C \end{aligned}\)
According to Curie law for paramagnetic substance
\(\chi_m \propto \frac{1}{T}\)
\(\frac{\chi_{m_1}}{\chi_{m_2}}=\frac{ T _2}{T_1}\)
\(\therefore \quad \frac{1.0 \times 10^{-5}}{1.5 \times 10^{-5}}=\frac{ T _2}{300}\)
\(\begin{aligned} T _2 =\frac{300}{1.5} \\ =200 K \\ =-73{ }^{\circ} C \end{aligned}\)
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