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GUJCET · Physics · Moving Charges and Magnetism
The galvanometer has a resistance of \(1.8 \Omega\). Calculate the value of shunt to increase the range of galvanometer by 10 times.
- A \(4 \Omega\)
- B \(1 \Omega\)
- C \(3 \Omega\)
- D \(2 \Omega\)
Answer & Solution
Correct Answer
(D) \(2 \Omega\)
Step-by-step Solution
Detailed explanation
D
Here,\(I_{G}=\left[\frac{r_s}{r_s+R_{G}}\right] I\)
\(\begin{array}{ll}\therefore \frac{ I }{10}=\left[\frac{r_s}{r_s+18}\right] I \\ \therefore r_s+18=10 r_s \\ \therefore 10 r_s-r_s=18 \\ \therefore 9 r_s=18 \\ \therefore r_s=2 \Omega\end{array}\)
Here,\(I_{G}=\left[\frac{r_s}{r_s+R_{G}}\right] I\)
\(\begin{array}{ll}\therefore \frac{ I }{10}=\left[\frac{r_s}{r_s+18}\right] I \\ \therefore r_s+18=10 r_s \\ \therefore 10 r_s-r_s=18 \\ \therefore 9 r_s=18 \\ \therefore r_s=2 \Omega\end{array}\)
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