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GUJCET · Physics · Moving Charges and Magnetism
To send \(10 \%\) of main current through moving coil galvanometer of resistance \(99 \Omega\). Shunt required is ________.
- A \(9 \Omega\)
- B \(11 \Omega\)
- C 108
- D \(99 \Omega\)
Answer & Solution
Correct Answer
(B) \(11 \Omega\)
Step-by-step Solution
Detailed explanation
B
Shunt \(S=\frac{G I_G}{I-I_G}\)
\(\begin{array}{l} S =\frac{99 \times 0.1}{1-0.1}\left(\because I _{ G }=10 \% I \right) \\ S =\frac{9.9}{0.9} \\ S=11 \Omega\end{array}\)
Shunt \(S=\frac{G I_G}{I-I_G}\)
\(\begin{array}{l} S =\frac{99 \times 0.1}{1-0.1}\left(\because I _{ G }=10 \% I \right) \\ S =\frac{9.9}{0.9} \\ S=11 \Omega\end{array}\)
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