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GUJCET · Maths · Matrices
If \(A=\left[\begin{array}{cc}\cos \theta & \sin \theta \\ -\sin \theta & \cos \theta\end{array}\right]\) then, \(A^3=\) ____________ .
- A \(\left[\begin{array}{cc}\cos 3 \theta & -\sin 3 \theta \\ \sin 3 \theta & \cos 3 \theta\end{array}\right]\)
- B \(\left[\begin{array}{cc}-\cos 3 \theta & \sin 3 \theta \\ \sin 3 \theta & \cos 3 \theta\end{array}\right]\)
- C \(\left[\begin{array}{cc}\cos 3 \theta & -\sin 3 \theta \\ -\sin 3 \theta & \cos 3 \theta\end{array}\right]\)
- D \(\left[\begin{array}{cc}\cos 3 \theta & \sin 3 \theta \\ -\sin 3 \theta & \cos 3 \theta\end{array}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[\begin{array}{cc}\cos 3 \theta & \sin 3 \theta \\ -\sin 3 \theta & \cos 3 \theta\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\( \mathrm{A}^n = \left[\begin{array}{cc}\cos n\theta & \sin n\theta \\ -\sin n\theta & \cos n\theta\end{array}\right] \) \( \mathrm{A}^3 = \left[\begin{array}{cc}\cos 3\theta & \sin 3\theta \\ -\sin 3\theta & \cos 3\theta\end{array}\right] \)
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