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GUJCET · Physics · Moving Charges and Magnetism
Current of 10 A and 2 A are passed through two parallel wires A and B respectively in opposite directions. If the wire \(A\) is infinitely long and length of the wire \(B\) is \(2 m\) the force acting on the conductor B which is situated at 10 cm distance from \(A\) will be _________.
- A \(4 \pi \times 10^{-7} N\)
- B \(5 \times 10^{-5} N\)
- C \(8 \pi \times 10^{-7} N\)
- D \(8 \times 10^{-5} N\)
Answer & Solution
Correct Answer
(D) \(8 \times 10^{-5} N\)
Step-by-step Solution
Detailed explanation
D
\(\begin{aligned} F & =\frac{\mu_0 I_1 I_2 l}{2 \pi y} \\ \therefore F & =\frac{4 \pi \times 10^{-7} \times 10 \times 2 \times 2}{2 \pi \times 10 \times 10^{-2}} \\ \therefore F & =8 \times 10^{-5} N\end{aligned}\)
\(\begin{aligned} F & =\frac{\mu_0 I_1 I_2 l}{2 \pi y} \\ \therefore F & =\frac{4 \pi \times 10^{-7} \times 10 \times 2 \times 2}{2 \pi \times 10 \times 10^{-2}} \\ \therefore F & =8 \times 10^{-5} N\end{aligned}\)
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