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GUJCET · Maths · Continuity and Differentiability
If \(y=\sin ^{-1}\left(\frac{2^{x+1}}{1+4^x}\right)\) and \(\frac{d y}{d x}=\frac{2^{x+1} \log 2}{f(x)}\) then, \(f(0)=\) _________
- A 2
- B 0
- C -2
- D \(2 \log 2\)
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
\(y = \sin^{-1}\left(\frac{2 \cdot 2^x}{1+(2^x)^2}\right)\) Let \(2^x = \tan\theta\). Then \(y = \sin^{-1}\left(\frac{2\tan\theta}{1+\tan^2\theta}\right) = \sin^{-1}(\sin(2\theta))\).
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