AP EAMCET · PHYSICS · Ray Optics
Two-point white dots are \(2 \mathrm{~mm}\) apart on a black paper. They are viewed by eye of pupil diameter \(3 \mathrm{~mm}\). What is the maximum distance at which these dots can be resolved by the eye? \((\lambda=500 \mathrm{~nm})\)
- A \(5 \mathrm{~m}\)
- B \(1 \mathrm{~m}\)
- C \(6 \mathrm{~m}\)
- D \(10 \mathrm{~m}\)
Answer & Solution
Correct Answer
(D) \(10 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Distance between two point white dots, \[ x=2 \mathrm{~mm}=2 \times 10^{-3} \mathrm{~m} \] Diameter of pupil, \(d=3 \mathrm{~mm}=3 \times 10^{-3} \mathrm{~m}\) and \(\quad \lambda=500 \mathrm{~mm}=5 \times 10^{-7} \mathrm{~m}\) If \(D\) be the maximum distance at which these two…
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