AP EAMCET · Maths · Three Dimensional Geometry
Line \(L_1\) passes through the points \(\bar{i}+\bar{j}\) and \(\bar{k}-\bar{i}\). Line \(L_2\) passes through the point \(\overline{\mathrm{j}}+2 \overline{\mathrm{k}}\) and is parallel to the vector \(\overline{\mathrm{i}}+\overline{\mathrm{j}}+\overline{\mathrm{k}}\). If \(\mathrm{x} \overline{\mathrm{i}}+\mathrm{y} \overline{\mathrm{j}}+\mathrm{z} \overline{\mathrm{k}}\) is the point of intersection of the lines \(L_1\) and \(L_2\), then \((y-x)=\)
- A \(2 z\)
- B \(-2 z\)
- C \(z\)
- D \(-z\)
Answer & Solution
Correct Answer
(C) \(z\)
Step-by-step Solution
Detailed explanation
\( \bar{r}_1 = (\bar{i}+\bar{j}) + \lambda ((\bar{k}-\bar{i})-(\bar{i}+\bar{j})) = (1-2\lambda)\bar{i} + (1-\lambda)\bar{j} + \lambda\bar{k} \) \( \bar{r}_2 = (\bar{j}+2\bar{k}) + \mu (\bar{i}+\bar{j}+\bar{k}) = \mu\bar{i} + (1+\mu)\bar{j} + (2+\mu)\bar{k} \)…
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