AP EAMCET · PHYSICS · Wave Optics
In Young's double slit experiment the slits are horizontal. The intensity at a point ' \(\mathrm{P}\) ' on the screen shown in the figure is \(\frac{\mathrm{I}_0}{4}\) where \(\mathrm{I}_0\) is maximum intensity. If the distance between the two slits \(S_1\) and \(S_2\) is \(2 \lambda\), then the value of ' \(\theta\) ' is

- A \(\cos ^{-1}\left(\frac{1}{6}\right)\)
- B \(\sin ^{-1}\left(\frac{1}{12}\right)\)
- C \(\tan ^{-1}\left(\frac{1}{6}\right)\)
- D \(\sin ^{-1}\left(\frac{3}{4}\right)\)
Answer & Solution
Correct Answer
(A) \(\cos ^{-1}\left(\frac{1}{6}\right)\)
Step-by-step Solution
Detailed explanation
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