AP EAMCET · PHYSICS · Alternating Current
A resistance of \(20 \Omega\) is connected to a source of an alternating potential \(\mathrm{V}=200 \sin (10 \pi \mathrm{t})\). If \(t\) is the time taken by the current to change from the peak value to rms value, then ' \(t\) ' is (in seconds).
- A \(25 \times 10^{-1}\)
- B \(2.5 \times 10^{-4}\)
- C \(25 \times 10^{-2}\)
- D \(2.5 \times 10^{-2}\)
Answer & Solution
Correct Answer
(D) \(2.5 \times 10^{-2}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=20 \Omega, \mathrm{~V}=200 \sin (10 \pi \mathrm{t})\) \(\therefore \quad I=\frac{V}{R}=10 \sin (10 \pi t)\) ....(i) \(\therefore \mathrm{I}_{\mathrm{o}}=10, \mathrm{I}_{\mathrm{rms}}=\frac{\mathrm{I}_{\mathrm{o}}}{\sqrt{2}}=\frac{10}{\sqrt{2}}\) \(\therefore\) From…
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