AP EAMCET · PHYSICS · Nuclear Physics
If \(200 \mathrm{MeV}\) of energy is released in the fission of one nucleus of \({ }_{92}^{236} \mathrm{U}\), the number of nuclei that must undergo fission to release an energy of \(1000 \mathrm{~J}\) is
- A \(3.125 \times 10^{13}\)
- B \(6.25 \times 10^{13}\)
- C \(12.5 \times 10^{13}\)
- D \(3.125 \times 10^{14}\)
Answer & Solution
Correct Answer
(A) \(3.125 \times 10^{13}\)
Step-by-step Solution
Detailed explanation
Energy released in the fission of one nucleus \(\begin{aligned} & =200 \mathrm{MeV} \\ & =200 \times 1.6 \times 10^{-13} \mathrm{~J} \\ & =3.2 \times 10^{-11} \mathrm{~J} \end{aligned}\) Energy to be released \(=1000 \mathrm{~J}\) \(3.2 \times 10^{-11} \mathrm{~J}\) energy is…
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