AP EAMCET · PHYSICS · Laws of Motion
Three blocks of masses \(2 \mathrm{~m}, 4 \mathrm{~m}\) and 6 m are placed as shown in figure.
If \(\sin 37^{\circ}=\frac{3}{5}, \sin 53^{\circ}=\frac{4}{5}\) the acceleration of the system is
- A \(a=\frac{17}{30} g\)
- B \(a=\frac{13}{30} g\)
- C \(a=\frac{13}{15} g\)
- D \(a=\frac{15}{35} g\)
Answer & Solution
Correct Answer
(A) \(a=\frac{17}{30} g\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & F_{n e t}=(2 m+4 m+6 m) a \\ \Rightarrow \quad & 10 \mathrm{mg} \sin 53^{\circ}-2 \mathrm{mg} \sin 37^{\circ}=12 \mathrm{ma}\end{aligned}\)…
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