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AP EAMCET · Maths · Vector Algebra

If \(\bar{a}\) and \(\bar{b}\) are not perpendicular to each other, \(\bar{r} \times \bar{a}=\bar{b} \times \bar{a}\) and \(\bar{r} \cdot \bar{c}=0\) then \(\bar{r}=\)

  1. A \(\bar{a}-\bar{c}\)
  2. B \(\bar{b}-\left(\frac{\bar{b} \cdot \bar{c}}{\bar{a} \cdot \bar{c}}\right) \bar{a}\)
  3. C \(\bar{b}+\left(\frac{\bar{b} \cdot \bar{c}}{\bar{a} \cdot \bar{c}}\right) \bar{a}\)
  4. D \(\bar{a}+\bar{c}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\bar{b}-\left(\frac{\bar{b} \cdot \bar{c}}{\bar{a} \cdot \bar{c}}\right) \bar{a}\)

Step-by-step Solution

Detailed explanation

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