AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
If two bodies of masses 2 kg and 3 kg are moving at right angles with velocities \(20 \mathrm{~m} \mathrm{~s}^{-1}\) and \(10 \mathrm{~m} \mathrm{~s}^{-1}\) respectively, then the velocity of the centre of mass of the system of the two bodies is
- A \(5 \mathrm{~m} \mathrm{~s}^{-1}\)
- B \(30 \mathrm{~m} \mathrm{~s}^{-1}\)
- C \(10 \mathrm{~m} \mathrm{~s}^{-1}\)
- D \(14 \mathrm{~m} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(C) \(10 \mathrm{~m} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\vec{V}_{CM} = \frac{m_1 \vec{v}_1 + m_2 \vec{v}_2}{m_1 + m_2}\) \(\vec{V}_{CM} = \frac{(2 \text{ kg})(20 \hat{i}) + (3 \text{ kg})(10 \hat{j})}{2 \text{ kg} + 3 \text{ kg}}\) \(\vec{V}_{CM} = \frac{40 \hat{i} + 30 \hat{j}}{5} = 8 \hat{i} + 6 \hat{j} \text{ m s}^{-1}\)…
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