AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The bond stability of \(\mathrm{N}_2, \mathrm{~N}_2^{-}\)and \(\mathrm{N}_2^{2-}\) varies as
- A \(\mathrm{N}_2 < \mathrm{N}_2^{-} < \mathrm{N}_2^{2-}\)
- B \(\mathrm{N}_2^{-} < \mathrm{N}_2 < \mathrm{N}_2^{2-}\)
- C \(\mathrm{N}_2^{2-} < \mathrm{N}_2^{-} < \mathrm{N}_2\)
- D \(\mathrm{N}_2^{-} < \mathrm{N}_2^{2-} < \mathrm{N}_2\)
Answer & Solution
Correct Answer
(C) \(\mathrm{N}_2^{2-} < \mathrm{N}_2^{-} < \mathrm{N}_2\)
Step-by-step Solution
Detailed explanation
Stability of a molecule is related with bond order as: Stability \(\propto\) Bond order Bond order of \(\mathrm{N}_2, \mathrm{~N}_2^{-}\)and \(\mathrm{N}_2^{-2}\) are 3, 2.5 and 2 respectively. Therefore, the bond stability order is…
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