AP EAMCET · PHYSICS · Current Electricity
A silver wire of length \(3 \mathrm{~m}\) and of cross-sectional area \(6.14 \times 10^{-6} \mathrm{~m}^2\) carries a current of 6 A. Atomic weight and density of silver are 108 and \(10500 \mathrm{kgm}^{-3}\), respectively. A silver atom contributes one free electron for conduction. Avogadro number is \(6.023 \times 10^{23} / \mathrm{mol}\). Drift velocity of electrons in silver is, close to
- A \(10^{-2} \mathrm{~ms}^{-1}\)
- B \(10^{-4} \mathrm{~ms}^{-1}\)
- C \(0.1 \mathrm{~ms}^{-1}\)
- D \(1 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(0.1 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, length of wire, \(l=3 \mathrm{~m}\) Cross-sectional area, \(A=6.14 \times 10^{-6} \mathrm{~m}^2\) Current in the wire, \(I=6 \mathrm{~A}\) Atomic weight of silver \(=108 \mathrm{amu}\) Density of silver, \(\rho=10500 \mathrm{kgm}^{-3}\)…
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