AP EAMCET · PHYSICS · Alternating Current
The impedance of an LR circuit with \(\mathrm{L}=\frac{60}{\pi} \mathrm{mH}\), \(\mathrm{R}=8 \Omega\) and frequency \(50 \mathrm{~Hz}\) is
- A \(1.3 \Omega\)
- B \(14.3 \Omega\)
- C \(20 \Omega\)
- D \(10 \Omega\)
Answer & Solution
Correct Answer
(D) \(10 \Omega\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{Z}=\sqrt{\mathrm{R}^2+\chi_{\mathrm{L}}^2}=\sqrt{\mathrm{R}^2+\omega^2 \mathrm{~L}^2} \\ & =\sqrt{8^2+\left(2 \pi \times 50 \times \frac{60}{\pi} \times 10^{-3}\right)} \\ & =\sqrt{8^2+6^2} \\ & =10 \Omega\end{aligned}\)
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