AP EAMCET · PHYSICS · Electrostatics
In a region of uniform electric field of intensity \(E\), an electron of mass \(m_e\) is released from rest. The distance travelled by the electron in a time \(t\) is
- A \(\frac{2 m_e t^2}{e}\)
- B \(\frac{e E t^2}{2 m_e}\)
- C \(\frac{m_e g t^2}{e E}\)
- D \(\frac{2 E t^2}{e m_e}\)
Answer & Solution
Correct Answer
(B) \(\frac{e E t^2}{2 m_e}\)
Step-by-step Solution
Detailed explanation
\(a=\frac{F}{m_e}=\frac{e E}{m_e}\) As, \(S=\frac{1}{2} a t^2=\frac{1}{2} \frac{e E}{m_e} t^2\)
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\begin{array}{|c|c|c|}
\hline List - I & & List - II \\
\hline A)Gauss's law & I) & Surface charge density \\
\hlineB) Faraday's law & II) & Electric charge and energy conservation \\
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\hline
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