AP EAMCET · Maths · Straight Lines
If all the normals drawn to the curve \(y=\frac{1+3 x^2}{3+x^2}\) at the points of intersection of \(y=\frac{1+3 x^2}{3+x^2}\) and \(y=1\) pass through the point \((\alpha, \beta)\), then \(3 \alpha+2 \beta=\)
- A 4
- B 2
- C -2
- D -4
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
\(\because y=\frac{1+3 x^2}{3+x^2}\) To get the intersection point, let us solve…
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