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AP EAMCET · Maths · Straight Lines

If all the normals drawn to the curve \(y=\frac{1+3 x^2}{3+x^2}\) at the points of intersection of \(y=\frac{1+3 x^2}{3+x^2}\) and \(y=1\) pass through the point \((\alpha, \beta)\), then \(3 \alpha+2 \beta=\)

  1. A 4
  2. B 2
  3. C -2
  4. D -4
Verified Solution

Answer & Solution

Correct Answer

(A) 4

Step-by-step Solution

Detailed explanation

\(\because y=\frac{1+3 x^2}{3+x^2}\) To get the intersection point, let us solve…