AP EAMCET · PHYSICS · Oscillations
The displacement of a particle of mass \(2 \mathrm{~g}\) executing SHM is given by \(y=5 \sin \left(4 t+\frac{\pi}{3}\right)\).
Here, \(y\) is in metres and \(t\) is in seconds.
The kinetic energy of the particle, when \(t=\frac{T}{4}\) is
- A \(0.4 \mathrm{~J}\)
- B \(0.5 \mathrm{~J}\)
- C \(3 \mathrm{~J}\)
- D \(0.3 \mathrm{~J}\)
Answer & Solution
Correct Answer
(D) \(0.3 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\begin{gathered} \text { Given, } y=5 \sin \left(4 t+\frac{\pi}{3}\right) \\ \omega=4 \text { and so } T=\frac{2 \pi}{4}=\frac{\pi}{2} \mathrm{~s} \\ t=\left[\frac{T}{4}=\frac{\pi}{8} \mathrm{~s}\right. \\ \text { Velocity }=\frac{d y}{d t}=20 \cos \left(4 t+\frac{\pi}{3}\right)…
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