AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A pressure of \(1 \mathrm{~mm}\) of mercury is equivalent to
- A \(1 \mathrm{mPa}\)
- B \(13.33 \mathrm{~Pa}\)
- C \(133.3 \mathrm{~Pa}\)
- D \(133.3 \mathrm{~Pa}\)
Answer & Solution
Correct Answer
(C) \(133.3 \mathrm{~Pa}\)
Step-by-step Solution
Detailed explanation
Height of mercury column \[ h=1 \mathrm{~mm}=10^{-3} \mathrm{~m} \] Density of mercury, \(\rho=13.6 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}\) \[ g=9.8 \mathrm{~ms}^{-2} \] \(\therefore\) Pressure, \(p=\rho g h\)…
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