AP EAMCET · PHYSICS · Thermal Properties of Matter
When \(50 \mathrm{~g}\) of water at \(10^{\circ} \mathrm{C}\) is mixed with \(50 \mathrm{~g}\) of water at \(100^{\circ} \mathrm{C}\). The resultant temperature is
- A \(80^{\circ} \mathrm{C}\)
- B \(55^{\circ} \mathrm{C}\)
- C \(25^{\circ} \mathrm{C}\)
- D \(45^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(55^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
If resulting temperature of the mixture is \(T^{\circ} \mathrm{C}\) then Heat gained by \(50 \mathrm{~g}\) water at \(10^{\circ} \mathrm{C}\), \(H_{\text {gain }}=m c \Delta T=50 c(T-10)\) Heat lost by \(50 \mathrm{~g}\) of water at \(100^{\circ} \mathrm{C}\)…
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