AP EAMCET · PHYSICS · Motion In Two Dimensions
A stone thrown with velocity ' \(u\) ' at angles ' \(\theta^{\prime}\) and \(\left(90^{\circ}-\theta\right)\) with the horizontal reaches to maximum heights \(\mathrm{H}_1\) and \(\mathrm{H}_2\) respectively. Its horizontal range is
- A \(4 \sqrt{\mathrm{H}_1 \mathrm{H}_2}\)
- B \(2 \mathrm{H}_1 \mathrm{H}_2\)
- C \(2 \sqrt{\mathrm{H}_1 \mathrm{H}_2}\)
- D \(\sqrt[4]{\frac{\mathrm{H}_1}{\mathrm{H}_2}}\)
Answer & Solution
Correct Answer
(A) \(4 \sqrt{\mathrm{H}_1 \mathrm{H}_2}\)
Step-by-step Solution
Detailed explanation
Maximum height, \(H=\frac{u^2 \sin ^2 \theta}{2 g}\) and horizontal range, \[ R=\frac{u^2 \sin 2 \theta}{g} \]…
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