AP EAMCET · PHYSICS · Magnetic Effects of Current
A proton of velocity a \((3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}) \mathrm{ms}^{-1}\) enters field of magnetic induction \((2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}})\) tesla, the acceleration produced in the proton in \(\mathrm{ms}^{-2}\) is \(\left(\right.\) Specific charge of proton \(=0.96 \times 10^8 \mathrm{Ckg}^{-1}\) )
- A \(28 \times 10^8(2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}})\)
- B \(288 \times 10^8(2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}})\)
- C \(28 \times 10^8(2 \hat{\mathbf{i}}+3 \hat{\mathbf{k}})\)
- D \(288 \times 10^8(\hat{\mathbf{i}}-3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}})\)
Answer & Solution
Correct Answer
(B) \(288 \times 10^8(2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}})\)
Step-by-step Solution
Detailed explanation
\(\mathbf{V}=(3 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}, \mathbf{B}=(2 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}) \mathrm{T}\) Specific charge \(\frac{e}{m}=0.96 \times 10^8 \mathrm{Ckg}^{-1}\) Force acting on the proton…
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