AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Hybridization of positively charged and negatively charged carbons of the following respectively are
- A \(\mathrm{sp}^2, \mathrm{sp}\)
- B \(\mathrm{sp}^2, \mathrm{sp}^2\)
- C \(\mathrm{sp}^3, \mathrm{sp}^3\)
- D \(\mathrm{sp}^3, \mathrm{sp}^2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{sp}^2, \mathrm{sp}\)
Step-by-step Solution
Detailed explanation
Positively- charged carbon in carbocation \(=\mathrm{sp}^2\) - hybridized due to three bond pairs and zero lone pairs. Negatively - charged carbon in carbanion \(=s p-\) hybridized due to one lone pair and one bond pair of electrons.
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