AP EAMCET · Maths · Probability
If eight coins are tossed simultaneously, then the probability of getting atleast six heads is
- A \(\frac{37}{64}\)
- B \(\frac{37}{512}\)
- C \(\frac{37}{256}\)
- D \(\frac{37}{128}\)
Answer & Solution
Correct Answer
(C) \(\frac{37}{256}\)
Step-by-step Solution
Detailed explanation
Since 8 coins are tossed simultaneously. Hence total samples \(=2^8=256=n(\mathrm{~S})\) Number of ways of getting at least 6 heads \(={ }^8 c_6+{ }^8 c_7+{ }^8 c_8=37=n(\mathrm{E})\) Therefore, Required probability \(=\frac{n(\mathrm{E})}{n(\mathrm{~S})}=\frac{37}{256}\)
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