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AP EAMCET · Maths · Circle

If the line \(4 x-3 y+7=0\) touches the circle \(x^2+y^2-6 x+4 y-12=0\) at \((\alpha, \beta)\), then \(\alpha+2 \beta=\)

  1. A \(3\)
  2. B \(-1\)
  3. C \(1\)
  4. D \(-3\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

Center of circle: \(C=(3, -2)\) Point of tangency \((\alpha, \beta)\) lies on line \(4x-3y+7=0\): \(4\alpha-3\beta=-7\) Radius from \(C\) to \((\alpha, \beta)\) is perpendicular to tangent line (slope \(4/3\)):…