AP EAMCET · PHYSICS · Nuclear Physics
A radioactive decay forms an isotope of the original nucleus with the emission of the following particles
- A one \(\alpha\) - and four \(\beta\)-particles
- B one \(\alpha\) - and one \(\beta\)-particles
- C one \(\alpha\) - and two \(\beta\)-particles
- D four \(\alpha\) - and one \(\beta\)-particles
Answer & Solution
Correct Answer
(A) one \(\alpha\) - and four \(\beta\)-particles
Step-by-step Solution
Detailed explanation
Isotopes are those atoms which have same atomic number and difference mass number \({ }_{\mathrm{z}}^{\mathrm{A}} \mathrm{X} \rightarrow \mathrm{z}_{\mathrm{Z}} \mathrm{Y}^{\mathrm{A}}+\alpha+2 \beta\) Hence \(1 \alpha\) and \(2 \beta\) particles will emit for the decay of…
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