AP EAMCET · PHYSICS · Rotational Motion
A circular disc of mass 20 kg and radius 1 m is rotating about an axis passing through its center and perpendicular to its plane with an angular velocity of \(2 \mathrm{rad} \mathrm{s}^{-1}\). Then the rotational kinetic energy of the disc is
- A 100 J
- B 50 J
- C 75 J
- D 20 J
Answer & Solution
Correct Answer
(D) 20 J
Step-by-step Solution
Detailed explanation
\( I = \frac{1}{2} m r^2 = \frac{1}{2} (20 \, \mathrm{kg}) (1 \, \mathrm{m})^2 = 10 \, \mathrm{kg} \, \mathrm{m}^2 \) \( KE_{rot} = \frac{1}{2} I \omega^2 = \frac{1}{2} (10 \, \mathrm{kg} \, \mathrm{m}^2) (2 \, \mathrm{rad} \, \mathrm{s}^{-1})^2 = 20 \, \mathrm{J} \)
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