AP EAMCET · Maths · Probability
The probability of a man hitting a target is \(\frac{2}{3}\), the minimum number of times he must fire so that the probability of hitting the target at least once is more then \(90 \%\)
- A 6
- B 3
- C 5
- D 4
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
Let X the number of times, he hits the targets. Hitting the target is a Bernoulli trial, So, X has a binomial distribution. \(\therefore \quad P(X=x)={ }^n C_x q^{n-x} p^x\) where, n = Number of times hit p = probability of hitting = 2/ 3 q = probability of not hitting = 1 − 2/…
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