AP EAMCET · Maths · Application of Derivatives
If the function \(f(x)=a x^3+b x^2+11 x-6\) satisfies the conditions of Rolle's theorem in \([1,3]\) and \(f^{\prime}\left(2+\frac{1}{\sqrt{3}}\right)=0\), then \(a+b=\)
- A -5
- B -3
- C 4
- D 7
Answer & Solution
Correct Answer
(A) -5
Step-by-step Solution
Detailed explanation
Given, \(f(x)=a x^3+b x^2+11 x-6\) satisfies the Rolle's theorem in \([1,3]\). So, \[ f(1)=0 \text { and } f(3)=0 \] \(\begin{array}{lrlrl}\text { and } & & 27 a+9 b+27 & =0 \\ \Rightarrow & & 9 a+3 b+9 & =0\end{array}\) From Eq. (i), we get \(a+b=-5\)
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