AP EAMCET · PHYSICS · Wave Optics
In a young's double slit experiment, the slits are separated by \(0.28 \mathrm{~mm}\) and the screen is placed \(1.4 \mathrm{~m}\) away from the slits. The distance between the central bright fringe and the 4 th order bright fringe is measured to be \(1.2 \mathrm{~cm}\). The wavelength of light used in this experiment is
- A \(2400 \mathrm{~nm}\)
- B \(600 \mathrm{~nm}\)
- C \(1200 \mathrm{~nm}\)
- D \(800 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(B) \(600 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
Distance between the slits, \(d=0.28 \mathrm{~mm}=0.28 \times 10^{-3} \mathrm{~m}\) Distance between the slits and the screen, \(D=1.4 \mathrm{~m}\) Distance between the central fringe and the fourth \((n=4)\) fringe, \[ u=1.2 \mathrm{~cm}=1.2 \times 10^{-2} \mathrm{~m} \] In…
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