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AP EAMCET · Maths · Straight Lines

The incenter of the triangle formed by the points \((0,0,0),(3,0,0)\) and \((0,4,0)\) is

  1. A \((1,1,0)\)
  2. B \((-1,-1,0)\)
  3. C \((1,0,1)\)
  4. D \((-1,0,-1)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \((1,1,0)\)

Step-by-step Solution

Detailed explanation

Let \(A(0,0,0), B(3,0,0), C(0,4,0)\) Now, \[ \begin{aligned} & a=\sqrt{(0-3)^2+(4-0)^2+(0-0)^2}=B C \\ & a=\sqrt{25}=5 \end{aligned} \] and \(b=A C=\sqrt{0+4^2+0}=4\) and \(c=A B=\sqrt{3^2+0+0}=3\) Now, coordinate of incentre \((x, y, z)\) is given as…
From AP EAMCET
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