AP EAMCET · PHYSICS · Electrostatics
A particle of mass 0.2 g and charge 2 C is released from rest in a uniform electric field of \(20 \mathrm{~N} \mathrm{C}^{-1}\). The kinetic energy of the particle after moving a distance of 20 cm is
- A 10 J
- B 8 J
- C 18 J
- D 12 J
Answer & Solution
Correct Answer
(B) 8 J
Step-by-step Solution
Detailed explanation
\(W = qEd\) \(KE = qEd\) \(KE = (2 \, \mathrm{C})(20 \, \mathrm{N \, C^{-1}})(0.2 \, \mathrm{m})\) \(KE = 8 \, \mathrm{J}\)
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