AP EAMCET · Maths · Indefinite Integration
If \(0 < a < 1\), then \(\int \frac{d x}{1-2 a \cos x+a^2}=\)
- A \(\frac{1}{1-a^2} \operatorname{Tan}^{-1}\left[\frac{1+a}{1-a} \tan \frac{x}{2}\right]+c\)
- B \(\frac{2}{1+a^2} \operatorname{Tan}^{-1}\left[\frac{1-a}{1+a} \tan \frac{x}{2}\right]+c\)
- C \(\frac{2}{1-a^2} \operatorname{Tan}^{-1}\left[\frac{1+a}{1-a} \tan \frac{x}{2}\right]+c\)
- D \(\frac{2}{1+a} \operatorname{Tan}^{-1}\left[\frac{1-a^2}{1+a^2} \tan \frac{x}{2}\right]+c\)
Answer & Solution
Correct Answer
(C) \(\frac{2}{1-a^2} \operatorname{Tan}^{-1}\left[\frac{1+a}{1-a} \tan \frac{x}{2}\right]+c\)
Step-by-step Solution
Detailed explanation
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